For a metal enclosure to stay safe during a fault, enough current must flow back through the equipment grounding conductor to trip the breaker instantly. This calculator builds the ground-fault loop impedance from the phase and grounding conductors, derives the prospective fault current, and checks it against the breaker’s instantaneous trip threshold per NEC 250.4(A)(5).
How it works
The fault current is limited by the round-trip loop impedance:
Z_loop = R_phase + R_egc + Z_source
I_fault = V_line-to-ground / Z_loop
trip threshold = instantaneous multiple × OCPD rating
pass if I_fault ≥ trip threshold
Conductor resistances come from the copper DC values in NEC Chapter 9 Table 8, scaled by the one-way run length. The instantaneous multiple models the breaker’s magnetic trip, where a standard thermal-magnetic breaker picks up around 10 times its rating.
How it works in an example
A 20 A breaker feeds a 100 ft run of 12 AWG copper with a 12 AWG ground at 120 V.
Each conductor adds about 1.98 Ω/1000 ft × 100 / 1000 = 0.198 Ω, so the loop is
roughly 0.198 + 0.198 = 0.396 Ω plus source impedance. The fault current is
about 120 / 0.45 ≈ 267 A, well above the 10 × 20 = 200 A instantaneous
threshold, so it passes.
Tips and notes
Lengthen the run or shrink the grounding conductor and the loop impedance climbs until the fault current can no longer reach the trip threshold. To fix a failing result, increase the equipment grounding conductor size, shorten the circuit, or add ground-fault protection. Remember this uses DC resistance, which suits small conductors and short branch circuits; for long feeders or large conductors, switch to the full alternating-current impedance method that includes reactance.