Ducts running through a blazing attic or a freezing crawlspace bleed real energy before the air ever reaches the room. This calculator estimates the conductive heat gain or loss through the duct walls from the surface area, insulation R-value, and the temperature difference between the duct air and the surrounding unconditioned space.
How it works
Conductive heat transfer through an insulated surface is governed by the simple steady-state relation:
Q (BTU/h) = A (ft²) × ΔT (°F) / R
A = duct surface area (entered, or π × diameter × length for round duct)
ΔT = | duct air temp − surrounding space temp |
R = duct insulation R-value (h·ft²·°F / BTU)
If the surrounding space is hotter than the duct air, the duct gains heat (a penalty on cooling); if the space is colder, the duct loses heat (a penalty on heating). The result is the conductive component only.
Example and notes
A round 12-inch supply duct, 30 feet long, has a surface area of about π × 1.0 × 30 = 94 square feet. Carrying 55 degree cooled air through a 130 degree attic with R-6 insulation gives Q = 94 × 75 / 6 = about 1,175 BTU/h of heat gain — heat that loads your air conditioner without cooling any room. Doubling the insulation to R-8 cuts it to about 880 BTU/h. Remember this ignores air leakage; sealing joints with mastic is just as important as adding insulation.