Orbital Period Calculator

Compute how long one orbit takes with Kepler's third law.

Calculate the orbital period of a satellite, planet or moon from the central mass and semi-major axis using Kepler's third law. Presets for the Sun, Earth and Jupiter. Runs entirely in your browser. It runs free in your browser on Gera Tools, with nothing uploaded.

Last updated Source: Gera Tools

What is the orbital period?

It is the time an object takes to complete one full orbit around a central body.

Using Kepler’s third law, this tool finds how long one orbit takes from the central mass and the orbit’s semi-major axis. It works for satellites around a planet, moons, or planets around a star — anything dominated by a single central gravitational body.

How it works

The period comes from Kepler’s third law in Newtonian form:

T = 2π · √(a³ ÷ GM)

where a is the semi-major axis in metres, M is the central mass in kilograms, and G is the gravitational constant, 6.6743 × 10⁻¹¹ m³ kg⁻¹ s⁻². The tool converts your axis from kilometres to metres, applies the formula to get the period in seconds, then also displays it in days (÷ 86,400) and years (÷ 31,557,600). Presets fill in the mass of the Sun, Earth, Jupiter or the Moon.

Reference examples

Earth orbiting the Sun (the defaults): M = 1.989 × 10³⁰ kg and a = 149,597,870 km (1 AU = 1.496 × 10¹¹ m).

  • T = 2π · √((1.496×10¹¹)³ ÷ (6.6743×10⁻¹¹ × 1.989×10³⁰))
  • T ≈ 3.156 × 10⁷ seconds ≈ 365.25 days ≈ 1 year
Central bodySemi-major axisPeriod
Sun1 AU (Earth)≈ 365 days
Sun1.52 AU (Mars)≈ 687 days
Sun5.2 AU (Jupiter)≈ 11.9 years
Sun9.54 AU (Saturn)≈ 29.5 years
Earth6371 km (surface)≈ 84 minutes
Earth6771 km (LEO, 400 km up)≈ 92 minutes
Earth42,164 km (GEO)≈ 24 hours
Earth384,400 km (Moon)≈ 27.3 days

Geostationary orbit at 42,164 km gives exactly one day — that is what keeps communication and weather satellites fixed over one point on the ground.

Understanding the inputs

Semi-major axis is half the longest diameter of an elliptical orbit. For a circular orbit it equals the orbital radius. For an elliptical orbit it is the average of the closest approach (periapsis) and the farthest point (apoapsis):

a = (periapsis + apoapsis) / 2

Central mass dominates the system. Kepler’s third law in this form ignores the orbiting body’s mass, which is valid whenever the satellite is much lighter than the central body — true for all planets around the Sun and for spacecraft around planets.

Practical uses

  • Satellite mission planning. Match orbital period to a communications window or a ground-track repeat cycle by adjusting the semi-major axis.
  • Astronomy homework. Check your worked solutions for planetary orbits by entering the planet’s actual semi-major axis.
  • Space game design. Generate realistic orbital periods for fictional star systems by setting a custom central mass.
  • Checking existing orbits. Enter a known satellite’s altitude to verify its published period matches Kepler’s prediction.

All values are computed in your browser; nothing is uploaded.