The neutral of a feeder rarely carries the same current as the phase conductors, and the National Electrical Code lets you take advantage of that — but only in specific cases. This calculator applies NEC 220.61 to find the neutral demand load and warns you when a full-size neutral is mandatory because of harmonic (non-linear) loads.
How it works
The starting point is the maximum unbalanced load — the largest net computed load between the neutral and any single ungrounded (phase) conductor.
NEC 220.61(B)(1) permits a reduction on the part of that load over 200 A:
neutral demand = first 200 A (at 100%) + (load over 200 A) × 0.70
So a 260 A maximum unbalanced load becomes 200 + 60 × 0.70 = 242 A.
That reduction is not always allowed. NEC 220.61(C) removes it for:
- The portion of load that is non-linear on a 4-wire, 3-phase wye system — triplen harmonics add arithmetically in the shared neutral rather than cancelling, so the neutral can carry as much current as a phase.
- 3-wire feeders from a wye, where the neutral carries full line current.
When those conditions hit, the tool flags a full-size neutral and counts it as a current-carrying conductor for ampacity-adjustment purposes.
Worked example
A 277/480 V wye panel feeds a mix of office lighting and receptacles. The most-loaded phase shows a 260 A unbalanced load and 60% of it is electronic (non-linear).
Because non-linear content is at or above 50% on a 4-wire wye, the 70% reduction is blocked. The neutral must be sized for the full 260 A, the same as the phase conductors — not the 242 A you would get from the reduction alone.
Notes and tips
- The 200 A threshold is a fixed Code value, not a percentage — always count the first 200 A at 100%.
- Harmonic-rich panels (lots of switch-mode supplies) often warrant an oversized neutral, sometimes 200% of the phase ampacity, even where the Code minimum would be smaller.
- This is a planning aid. Confirm the final size against the applicable ampacity table, ambient and conductor-fill derates, and your local inspector.
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