Simplified Manual J Heat Load Calculator

Estimate residential heating and cooling loads for equipment sizing room-by-room

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Right-sizing heating and cooling equipment starts with an honest load calculation, not a per-square-foot rule of thumb. This simplified Manual J tool sums conduction through the building envelope, infiltration, and solar gain through glass to estimate peak heating and cooling loads you can use to sanity -check equipment selection.

How it works

Loads are built from the classic envelope equations. Conduction through each surface and infiltration use the design temperature difference; cooling adds solar gain through glass:

conduction   = Σ (U × area × ΔT)          for walls, ceiling, floor, windows
infiltration = 1.08 × CFM × ΔT            CFM = ACH × volume / 60
solar gain   = window area × SHGC × peak solar factor   (cooling only)
heating load = conduction(ΔT_heat) + infiltration(ΔT_heat)
cooling load = conduction(ΔT_cool) + infiltration(ΔT_cool) + solar gain
tons         = cooling load / 12,000

The factor 1.08 converts CFM and a temperature difference to sensible BTU/h at standard air. Twelve thousand BTU/h equals one ton of cooling, the unit equipment is rated in.

Example and tips

A room with 300 square feet of net wall at U 0.07, 200 square feet of ceiling at U 0.03, 40 square feet of window at U 0.45 and SHGC 0.35, with a 70-degree heating and 20-degree cooling difference, lands near 5,000 BTU/h heating and roughly half a ton of cooling. Always subtract window area from gross wall area before entering it, and remember a simplified estimate omits internal gains, duct losses and latent load — a full Manual J will run somewhat higher on cooling.

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