The kW to kVA calculator converts real power (kilowatts) into apparent power (kilovolt-amperes) using the power factor — the single most important number when sizing generators, UPS systems, transformers, switchgear and cables. Every electrical installation has a power triangle connecting three quantities: real power P (kW), apparent power S (kVA) and reactive power Q (kVAR). Get the triangle wrong and you under-rate equipment, overload circuits or pay unnecessary demand charges on your electricity bill.
This tool computes all three sides of that triangle from a single kW and power-factor entry. It also derives the phase angle, an estimate of the current your load draws at standard voltage, and a full reference table so you can compare kVA across a range of power factors without re-entering values.
How it works
The fundamental formula is:
kVA = kW ÷ PF
where PF is the power factor — a dimensionless number from 0 to 1. At PF = 1.0 (a purely resistive load such as an electric heater), kVA equals kW exactly: all apparent power is real power. As inductance increases and PF falls toward 0.8 or lower, the kVA figure climbs above kW, meaning the supply must deliver more current than the useful work alone would require.
From the primary result the tool then calculates:
- Reactive power Q — using the power-triangle identity Q = sqrt(S² - P²), expressed in kVAR.
- Phase angle θ — arccos(PF), the angle between the voltage and current phasors, in degrees.
- Estimated current — rearranging S = V × I (single-phase) or S = √3 × V × I (three-phase) to give I = S × 1000 ÷ V (single) or I = S × 1000 ÷ (√3 × V) (three-phase), using 230 V and 400 V as reference voltages respectively.
The voltage/current panel also runs the calculation in reverse: enter measured volts and amps and the tool derives kVA directly, then applies the power factor to give kW as well.
Worked example
A 15 kW motor runs at a power factor of 0.85:
- Apparent power: 15 ÷ 0.85 = 17.65 kVA
- Reactive power: sqrt(17.65² - 15²) = 9.29 kVAR
- Phase angle: arccos(0.85) = 31.79°
- Current at 400 V (3-phase): 17.65 × 1000 ÷ (√3 × 400) = 25.49 A
If you specified a generator purely on kW you would look for a 15 kW set, but you actually need one rated for at least 17.65 kVA — otherwise the reactive current overloads the alternator windings even though the real-power demand appears within limits.
Formula note
The power triangle obeys Pythagoras in the phasor domain:
S² = P² + Q² PF = P ÷ S = cos(θ) Q = S × sin(θ)
For three-phase circuits the apparent power from line voltage and current is:
S (kVA) = √3 × V_L × I_L ÷ 1000
where V_L is the line-to-line (phase-to-phase) voltage and I_L is the line current. The √3 factor (approximately 1.7321) accounts for the 120° separation between phases. The kW-to-kVA formula itself (kVA = kW ÷ PF) is the same for both single- and three-phase systems.
All arithmetic runs locally in your browser — no values are uploaded or stored.