Keeping gas pressure where it belongs
A fuel gas pipe must deliver enough gas to every appliance without dropping the pressure below what the burners need. NFPA 54 and the IPC let designers size low-pressure systems so the total pressure loss stays within a small allowance — commonly 0.3 inches of water column. This calculator computes the drop through a pipe segment so you can confirm a run is large enough before it goes in the wall.
How it works
For low-pressure gas the code references the Spitzglass formula. Its
low-pressure form relates flow to the square root of diameter to the fifth power
times pressure drop, divided by length and specific gravity, with a
diameter-dependent friction factor Cr = 1 / sqrt(1 + 3.6/D + 0.03·D). Solving
for the pressure drop gives:
H = ( Q / (3550 · Cr) )^2 · ( Cg · L ) / D^5
where H is the drop in inches of water column, Q is flow in SCFH, D is the
actual inside diameter in inches, Cg is gas specific gravity (0.60 for natural
gas, 1.52 for propane), and L is length in feet. The tool uses Schedule 40
steel inside diameters and back-calculates the heat input from your flow using
the gas heating value.
Example and notes
A 150 SCFH natural-gas load through 40 ft of 3/4″ Schedule 40 pipe drops
well under 0.3 in WC, so the run passes. Increase the flow or length and the
drop climbs with the square of flow and linearly with length, so doubling the
run doubles the loss. Always add equivalent lengths for fittings, check the
longest path to the most remote appliance, and confirm the delivered manifold
pressure — about 3.5 in WC for natural gas and 11 in WC for propane — is still
met.