Electric heat trace replaces the heat an insulated pipe loses to a cold environment so the fluid inside never freezes or drops below a process minimum. This calculator works out the heat loss per foot of pipe and then selects the nearest standard self-regulating cable so the line stays warm at your design ambient.
How it works
Heat flows radially out through the insulation. For a cylinder the steady-state conduction loss per unit length is:
Q = 2 · π · k · (T_maintain − T_ambient) / ln(r_outer / r_inner)
where k is the insulation thermal conductivity, r_inner is the pipe outer
radius and r_outer is the radius over the insulation. The result is in watts
per metre, which the tool converts to watts per foot. A safety factor is applied
for wind, wet insulation and fittings, then the tool picks the lowest standard
self-regulating cable rating (3, 5, 8, 10 or 12 W/ft) that still exceeds the
adjusted loss.
Example and notes
A 2-inch steel pipe (≈2.375 in OD) with 1 inch of fiberglass insulation
(k ≈ 0.04 W/m·K), maintaining 40 °F against a −10 °F design ambient, loses
roughly 4 W/ft. With a 20 percent margin that becomes about 4.8 W/ft, so a
standard 5 W/ft self-regulating cable is selected. Doubling the insulation to
2 inches cuts the loss enough to drop to a 3 W/ft cable. Always confirm the cable
is rated for your pipe material and that the branch circuit and ground-fault
protection match the manufacturer’s maximum circuit length.