How is each character turned into binary?

The text is first encoded as UTF-8 bytes. Each byte (0 to 255) is then written as an 8-bit binary string, zero-padded on the left. A capital A is byte 65, which is 01000001.

Why do some characters produce more than eight bits?

Non-ASCII characters such as accented letters or emoji are multiple UTF-8 bytes, so each contributes one 8-bit group per byte. A single emoji can therefore expand to four 8-bit groups, or 32 bits.

Does the decoder need spaces between bytes?

No. The decoder strips all whitespace, then reads the bits in groups of eight from left to right. As long as the total bit count is a multiple of eight, it reconstructs the bytes and decodes them as UTF-8.

What happens if the binary is invalid?

If the input contains characters other than 0 and 1, or the bit count is not a multiple of eight, the tool reports the problem instead of guessing. This avoids silently producing garbled text.

Is the round trip lossless?

Yes. Encoding text to binary and decoding it back returns the original string exactly, including spaces, punctuation, and Unicode characters, because UTF-8 is a lossless encoding.

Binary Text Converter

This converter translates between human text and 8-bit binary. Encoding turns each UTF-8 byte of your text into a zero-padded group of eight bits; decoding reads such groups back into the original characters.

How it works

For encoding, the text is converted to UTF-8 bytes (via TextEncoder). Each byte is a number from 0 to 255, written as eight binary digits:

byte 65 (A) -> 01000001
byte 32 ( ) -> 00100000

For decoding, all whitespace is removed and the remaining 0 and 1 characters are split into groups of eight. Each group is parsed as a byte and the resulting byte array is decoded as UTF-8 back into text.

Example and notes

The word Hi is bytes 72 and 105, giving 01001000 01101001. ASCII characters always fit in one 8-bit group, but anything outside ASCII uses multiple UTF-8 bytes and therefore multiple groups. When decoding, the bit count must be an exact multiple of eight; otherwise the tool flags the input as malformed rather than dropping bits.