Why can't a normal calculator handle big integers?

JavaScript and most calculators use 64-bit floating-point, which is only exact up to about 9 quadrillion (2^53). Beyond that, digits are silently rounded. BigInt stores integers of any size exactly, so results stay precise.

How does integer division work here?

Division gives the integer quotient (truncated toward zero) and the remainder, since BigInt does not produce fractions. For example 17 divided by 5 is quotient 3, remainder 2. Dividing by zero is rejected.

What about the power operation?

Power raises the first integer to the second. Because results grow extremely fast, the exponent is capped at a reasonable size to keep the page responsive — but within that range the result is exact.

Are negative numbers supported?

Yes for add, subtract, and multiply. Modulo follows BigInt's sign rule where the remainder takes the sign of the dividend, and the power exponent must be non-negative since negative powers are not integers.

Big Integer Calculator

This calculator does exact arithmetic on integers of any size — far beyond the floating-point limit where ordinary calculators silently lose precision. It uses JavaScript’s BigInt, so a 200-digit multiplication is correct to the last digit.

How it works

Each operand is parsed as a BigInt and the chosen operation is applied with exact integer semantics:

add       a + b
subtract  a - b
multiply  a × b
divide    quotient = a / b (truncated),  remainder = a % b
modulo    a % b
power     a ^ b   (b ≥ 0)

Division and modulo follow BigInt’s truncated rule: the quotient rounds toward zero and the remainder takes the sign of the dividend. Division or modulo by zero is rejected rather than producing a meaningless result.

Example and tips

Multiplying two 30-digit numbers gives a precise 59- or 60-digit product that a float-based calculator would mangle. For 17 ÷ 5, you get quotient 3 and remainder 2. If you need modular exponentiation specifically, the dedicated modular-exponentiation tool is far faster for large exponents because it reduces modulo m at every step.